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Algebraic Identity (a³ - b³)
Algebraic Identity (a³ - b³)
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1)
Solve by Algebraic Identity 8x³-1=0.
1/2
1/5
1/4
1/3
2)
Simplify the expression (2x)³ - (3y)³
8x³ - 9y³
8x³ - 6x²y+9x-27y³
8x³ - 12xy²+9y³
8x³ - 27y³
3)
Find the value of (5a³ - 2b³) if a = 2 and b = 1
40
38
28
39
4)
Simplify the expression (3p)³ - (4q)³
9p² + 12pq + 16q²
3p - 4q
9p³ - 16q³
(3p - 4q)(9p² + 12pq + 16q²)
5)
Find the value of (5a³ - 2b³) if a = 5 and b = 1
623
523
613
633
6)
Write the factors of a3 – b3
a³-3a²b+3ab²+b³
(a – b)(a2 + b2 + ab)
(a – b)(a + b)
(a – b)(a2 + b2 - ab)
7)
Find 8³ – 3³ by using algebraic identity a³-b³ =?
486
485
484
480
8)
What is the value of 3³ – 2³. Calculate by using algebraic identity a³-b³.
19
15
21
17
9)
Factorize: 27x³ – 64y³
(3x-4y)(9x²+16y²+15xy)
(3x-4y)(9x²+16y²+12xy)
(3x-4y)(9x²+18y²+12xy)
(3x-6y)(9x²+16y²+12xy)
10)
If a=0 cm and b=7 cm then a³ – b³ =?
343 cm³
-350 cm³
0 cm³
-343 cm³