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Algebraic Identity (a³+b³)
Algebraic Identity (a³+b³)
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1)
Find 5³ + 2³ by using formula a³ + b³ = (a+b) (a² – ab + b²).
129
169
133
150
2)
Simplify: (3x + 1) (9x² + 1 — 3x) by using identity
(3x³ + 1)
(27x³ + 1)
(9x² + 1)
(9x² - 1)
3)
Find the factors of (27x³ + 125).
(3x + 5) (9x² – 15x + 25)
(3x + 5)(3x - 5)
(3x - 5)³
(3x + 5)³
4)
How many factors are formed by x³ + y³?
3
1
2
4
5)
Write the factors of (x – 1)³+(y – 1)³
(x + y – 2)(x² + y² – x – y – xy + 1)
(x – 1)(y – 1)
(x + y + 2)(x² - y² + x – y – xy - 1)
(x – 1 + y – 2)(x² + y² – 1)
6)
Simplify the expression (2x)³+(3y)³
8³x³ - 27³y³
8x³ + 27y³
8x³ - 27y³
8³x³ + 27³y³
7)
Factorize the expression 8x³ + 27y³
(2x-3y)(4x²+6xy+9y²)
(2x+3y)(4x²−6xy+9y²)
(2x-3y)(4x²−6xy+9y²)
(2x+3y)(4x²+6xy+9y²)
8)
Factorize the expression a³+8b³
(a-2b)(a²+2ab+4b²)
(a+2b)(a²+2ab+4b²)
(a+2b)(a²−2ab+4b²)
(a-2b)(a²−2ab+4b²)
9)
Simplify the expression x³+8
(x+2)(x²−2x+4)
(x+2)³
x³+8
x³−2x+8
10)
Factorize the expression 8+y³
(2-y)(4−2y+y²)
(2+y)(4−2y+y²)
(2-y)(4+2y+y²)
(2+y)(4+2y+y²)