To show that the area of rhombus is half the product of its diagonals.
In above figure EHGF is rhombus with diagonal HF (length d1) and diagonal EG (length d2)
Area of rhombus EHGF = Area of triangle EFH + Area of triangle FHG
= half of the product of the diagonals
Find the area of the following rhombus.
In the given figure,
PR = d1= 24 cm.
SQ = d2 = 18 cm.
So, the area of the rhombus PQRS is 216 cm2.