Area of rhombus

To show that the area of rhombus is half the product of its diagonals.

- A rhombus is a simple (non-self-intersecting) quadrilateral whose all four sides are of same length.
- If a parallelogram has two consecutive sides congruent, it is a rhombus.
- If two triangles are congruent then their areas are equal.
- Area of a triangle = 1/2 X base X height
- Area of a rectangle = Length X Breadth
- Diagonals of rhombus are perpendicular to each other.

In above figure EHGF is rhombus with diagonal HF (length d_{1)} and diagonal EG (length d_{2)}

Area of rhombus EHGF = Area of triangle EFH + Area of triangle FHG

= half of the product of the diagonals

Find the area of the following rhombus.

In the given figure,

PR = d_{1}= 24 cm.

SQ = d_{2 }= 18 cm.

So, the area of the rhombus PQRS is 216 cm^{2}.